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1. The present ratio of ages of A and B is 4 : 5. 18 years ago, this ratio was 11 : 16. Find the sum total of their present ages.
18 years ago their ages
Or, 64x - 288 = 55x - 198
Or, 64x - 55x = -198 + 288
Or, 9x = 90
Or, x = = 10
Sum of the present ages = 40 + 50 = 90 years
Solution:
Let present age of A and B be 4x and 5x18 years ago their ages
Or, 64x - 288 = 55x - 198
Or, 64x - 55x = -198 + 288
Or, 9x = 90
Or, x = = 10
Sum of the present ages = 40 + 50 = 90 years