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1. The product of two numbers is 120 and the sum of their squares is 289. The sum of the number is:
Then, xy = 120 and x2 + y2 = 289
∴ (x + y)2 = x2 + y2 + 2xy = 289 + (2 x 120) = 529
∴ x + y = = 23
Solution:
Let the numbers be x and yThen, xy = 120 and x2 + y2 = 289
∴ (x + y)2 = x2 + y2 + 2xy = 289 + (2 x 120) = 529
∴ x + y = = 23