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1. The ratio between a two-digit number and the sum of the digits of that number is 4 : 1. If the digit in the unit's place is 3 more than the digit in the ten's place, then the number is ?

Solution:
Let the ten's digit be x
Then, units digit = x + 3
Number = 10x + (x + 3)
              = 11x + 3
Sum of digits = x + (x + 3)
                      = 2x + 3
∴11x+32x+3=41⇔11x+3=8x+12⇔3x=9⇔x=3
Hence, Required number
= 11x + 3
= 11 × 3 + 3
= 36

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