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1. The remainder of $\frac{6^{36}}{215} :$

A. 0

B. 1

C. 2

D. 3

Solution:

\begin{aligned} \frac{6^{36}}{215}, can be written as \\ \frac{{(6^{3})}^{12}}{215} \\ O r, \frac{216^{12}}{215}, [216 on divided by 215, gives remainder 1] \\ \frac{1^{12}}{215} \\ The remainder will be 1 \end{aligned}

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