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1. The remainder when 1010 + 10100 + 101000 + . . . . . . + 101000000000 is divided by 7 is

Solution:
Number of terms in the series = 10.
(We can get it easily by pointing the number of zeros in power of terms.
In 1st term number of zero is 1, 2nd term 2, and 3rd term 3 and so on.)
10107,   Written as, (7+3)(4×2+2)7
The remainder will depend on 327
So, remainder will be 2
1010007,remainder=210100007,remainder=1
So, we get alternate 2 and 1 as remainder, five times each.
So, required remainder is given by
(2+1+2+1+2+1+2+1+2+1)7=157
Remainder when 15 is divided by 7 = 1

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