Practice | Hashtable

1. The slant height of a right circular cone is 10 m and its height is 8 m. Find the area of its curved surface.

A. 30π m²

B. 40π m²

C. 60π m²

D. 80π m²

Solution:

\begin{aligned} l = 10 m \\ h = 8 m \\ S o, r = \sqrt{l^{2} - h^{2}} = \sqrt{{(10)}^{2} - 8^{2}} = 6 m \\ ∴ Curved surface area \\ π r l = (π \times 6 \times 10) m^{2} \\ = 60 π m^{2} \end{aligned}

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