Home > Practice > Arithmetic Aptitude > HCF & LCM of Numbers > Miscellaneous
1. The smallest number, which when increased by 5 is divisible by each of 24, 32, 36 and 64 is ?
⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571
Solution:
LCM of (24, 32, 36, 64)⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571