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1. Two dice are thrown simultaneously. Find the probability of getting a multiple of 2 on one dice and multiple of 3 on the other dice.

A. $\frac{5}{12}$

B. $\frac{11}{36}$

C. $\frac{5}{36}$

D. $\frac{13}{36}$

Solution:

Let X be required events and S be the sample space
then X = {(2, 3), (2, 6), (4, 3), (4, 6), (6, 3), (6, 6), (3, 2), (6, 2), (3, 4), (6, 4), (3, 6)}
n(X) = 11, n(S) = 36
Hence, required probability

\begin{aligned} = \frac{n (X)}{n (S)} \\ = \frac{11}{36} \end{aligned}

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