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1. Two pipes can fill a tank in 12 hours and 16 hours respectively. A third pipe can empty the tank in 30 hours. If all three pipes are opened and functions simultaneously, how much time will the tank take to be full?( in hours )
Second pipe fill the tank in 1 hour = part of tank
Third pipe empty the tank in 1 hour = part of tank
When all three pipes are opened simultaneously, part of the tank filled in 1 hour
LCM of 12, 16 and 30 = 240
∴ Required time taken by all the three pipes
Solution:
First pipe fill the tank in 1 hour = part of tankSecond pipe fill the tank in 1 hour = part of tank
Third pipe empty the tank in 1 hour = part of tank
When all three pipes are opened simultaneously, part of the tank filled in 1 hour
LCM of 12, 16 and 30 = 240
∴ Required time taken by all the three pipes