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1. Two pipes can fill a tank in 12 hours and 16 hours respectively. A third pipe can empty the tank in 30 hours. If all three pipes are opened and functions simultaneously, how much time will the tank take to be full?( in hours )

Solution:
First pipe fill the tank in 1 hour = 112 part of tank
Second pipe fill the tank in 1 hour = 116 part of tank
Third pipe empty the tank in 1 hour = 130 part of tank
When all three pipes are opened simultaneously, part of the tank filled in 1 hour
=112+116130
LCM of 12, 16 and 30 = 240
 = 20+158240=27240
∴ Required time taken by all the three pipes
 = 24027=809=889Hours

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