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1. Two ports A and B are 300 km apart. Two ships leave A for B such that the second leaves 8 hours after the first. The ships arrive at B simultaneously. Find the time the slower ship spent on the trip if the speed of one of them is 10 km/h higher than that of the other.
Let speed of the 1st ship is s kmph and speed of 2nd ship is (s + 10) kmph.
Let 2nd ship takes time t to cover the distance 300 km then 1st ship takes (t + 8) hours.
As distance is constant, we have,
Or, st + 8s = st + 10t
Or, 8s = 10t
If the slower ship took 20 hours (option D) the faster ship would take 12 hours and their respective speeds would be 15 and 25 kmph.
Solution:
A__________300 km_______BLet speed of the 1st ship is s kmph and speed of 2nd ship is (s + 10) kmph.
Let 2nd ship takes time t to cover the distance 300 km then 1st ship takes (t + 8) hours.
As distance is constant, we have,
Or, st + 8s = st + 10t
Or, 8s = 10t
If the slower ship took 20 hours (option D) the faster ship would take 12 hours and their respective speeds would be 15 and 25 kmph.