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1. Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

A. 36

B. 45

C. 48

D. 49

Solution:

\begin{aligned} Relative speed = (60 + 90) km/hr \\ = 150 \times \frac{5}{18} m/sec \\ = \frac{125}{3} m/sec \\ Distance covered \\ = (1.10 + 0.9) k m \\ = 2 k m \\ = 2000 m \\ Required time \\ = 2000 \times \frac{3}{125} sec \\ = 48 s e c \end{aligned}

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