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1. Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?

A. 23 m

B. $23 \frac{2}{9}$ m

C. $27 \frac{7}{9}$ m

D. 29 m

Solution:

\begin{aligned} Relative speed = (40 - 20) km/hr \\ = (20 \times \frac{5}{18}) m/sec \\ = \frac{50}{9} m/sec \\ ∴ Length of faster train \\ = (\frac{50}{9} \times 5) m \\ = \frac{250}{9} m \\ = 27 \frac{7}{9} m \end{aligned}

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