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1. Two typist of varying skills can do a job in 6 minutes if they work together. If the first typist typed alone for 4 minutes and then the second typist typed alone for 6 minutes, they would be left with of the whole work. How many minutes would it take the slower typist to complete the typing job working alone ?
= = 16.66% per minute
Now, let work efficiency of first typist be x and then second typist will be (16.66 - x)
First typist typed alone for 4 minutes and second typed alone for 6 minutes and they left with (i.e 20%) of job, means they have completed 80% job
Now,
First Typist typed in 4 minute + Second typed in 6 minutes = 80%
4 × x + 6 × (16.66 - x) = 80%
4x + 100% - 6x = 80%
x = 10%
First Typist typed 10% per minutes. Then second typed (16.66 - 10) = 6.66% per minute
Then, Second typist complete the whole job in = 15.01 = 15 minutes.
Solution:
Working efficiency of both typist together,= = 16.66% per minute
Now, let work efficiency of first typist be x and then second typist will be (16.66 - x)
First typist typed alone for 4 minutes and second typed alone for 6 minutes and they left with (i.e 20%) of job, means they have completed 80% job
Now,
First Typist typed in 4 minute + Second typed in 6 minutes = 80%
4 × x + 6 × (16.66 - x) = 80%
4x + 100% - 6x = 80%
x = 10%
First Typist typed 10% per minutes. Then second typed (16.66 - 10) = 6.66% per minute
Then, Second typist complete the whole job in = 15.01 = 15 minutes.