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1. Walking $\frac{3}{4}$ of his normal speed, Rabi is 16 minutes late in reaching his office. The usual time taken by him to cover the distance between his home and office:

A. 48 min.

B. 60 min.

C. 42 min.

D. 62 min.

Solution:

1^st method:

\frac{4}{3}

of usual time = Usual time + 16 minutes;
Hence,

\frac{1}{3} rd

of usual time = 16 minutes;
Thus, Usual time = 16 × 3 = 48 minutes.

2^nd method:
When speed goes down to

\frac{3}{4} th

(i.e. 75%) time will go up to

\frac{4}{3} rd

(or 133.33%) of the original time.
Since, the extra time required is 16 minutes; it should be equated to

\frac{1}{3} rd

of the normal time.
Hence, the usual time required will be 48 minutes.

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