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1. What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

A. 814

B. 820

C. 840

D. 844

Solution:

\begin{aligned} Length of largest tile = \\ H .C .F . of 1517 c m and 902 c m = 41 c m \\ Area of each tile = (41 \times 41) c m^{2} \\ ∴ Required number of tiles \\ = \frac{1517 \times 902}{41 \times 41} \\ = 814 \end{aligned}

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