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1. What is the value of the following expression?
$\log (\frac{9}{14}) -$ $\log (\frac{15}{16}) +$ $\log (\frac{35}{24})$

A. 0

B. 1

C. 2

D. 3

Solution:

\begin{aligned} \log (\frac{9}{14}) - \log (\frac{15}{16}) + \log (\frac{35}{24}) \\ = \log (\frac{9}{14} \div \frac{15}{16} \times \frac{35}{24}) \\ = \log (\frac{9}{14} \times \frac{16}{15} \times \frac{35}{24}) \\ = \log 1 \\ = 0 \end{aligned}

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