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1. What least number must be subtracted from 1936 so that the resulting number when divided by 9, 10 and 15 will leave in each case the same remainder 7 ?

A. 37

B. 36

C. 39

D. 30

Solution:

\begin{aligned} LCM of (9, 10, 15) \\ = 3 \times 3 \times 10 \\ = 90 \\ \frac{1936}{90}, remainder  =  46 \end{aligned}

Least number when is subtracted from 1936 which gives remainder 7 when divided by (9, 10, 15) is = (46 - 7) = 39

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