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1. When six fair coins are tossed simultaneously, in how many of the outcomes will at most three of the coins turn up as heads?
i.e., 0 coins turn heads or 1 coin turns head or 2 coins turn heads or 3 coins turn heads.
The number of outcomes in which 0 coins turn heads is,
6C0 = 1 outcome.
The number of outcomes in which 1 coin turns head is,
6C1 = 6 outcomes.
The number of outcomes in which 2 coins turn heads is,
6C2 = 15 outcomes.
The number of outcomes in which 3 coins turn heads is,
6C3 = 20 outcomes.
Therefore, total number of outcomes
= 1 + 6 + 15 + 20
= 42 outcomes.
Solution:
The question requires you to find number of the outcomes in which at most 3 coins turn up as heads.i.e., 0 coins turn heads or 1 coin turns head or 2 coins turn heads or 3 coins turn heads.
The number of outcomes in which 0 coins turn heads is,
6C0 = 1 outcome.
The number of outcomes in which 1 coin turns head is,
6C1 = 6 outcomes.
The number of outcomes in which 2 coins turn heads is,
6C2 = 15 outcomes.
The number of outcomes in which 3 coins turn heads is,
6C3 = 20 outcomes.
Therefore, total number of outcomes
= 1 + 6 + 15 + 20
= 42 outcomes.