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1. In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:

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Solution:
A:B=100:90A:C=100:72B:C=BA×AC=90100×10072=9072
When B runs 90 m, C runs 72 m.
When B runs 100m, C run
(7290×100)m=80m
∴ B can give C 20 m
2. A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:

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Solution:
A'sspeed=(5×518)m/sec=2518m/secTimetakenbyAtocover 100 m=(100×1825)sec=72secTimetakenbyBtocover 92 m=(72+8)=80secB'sspeed=(9280×185)kmph=4.14 kmph
3. In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:

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Solution:
To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.
While A covers 3 m, B covers 4 m.
While A covers 360 m, B covers (43×360)  m = 480 m.
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
∴ A wins by 20 m.
4. In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:

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Solution:
A:B=100:90A:C=100:87BC=BA×AC=90100×10087=3029
When B runs180m, C runs (2930×180)m=174m
∴ B beats C by (180 - 174) m = 6 m
5. At a game of billiards, A can give B 15 points in 60 and A can give C to 20 points in 60. How many points can B give C in a game of 90?

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Solution:
A:B=60:45A:C=60:40BC=BA×AC=4560×6040=4540=9080=90:80BcangiveC10pointsinagameof90
6. In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by:

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Solution:
A:B=200:169A:C=200:182CB=CA×AB=182200×200169=182:169
When C covers 182 m, B covers 169 m
When C covers 350 m, B covers (169182×350)m=325m
∴ C beats B by (350 - 325) m = 25 m
7. In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:

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Solution:
Distance covered by B in 9 sec=(10045×9)m=20mA beats B by 20 metres
8. In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:

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Solution:
A:B=100:80A:C=100:72BC=BA×AC=80100×10072=109=10090=100:90BcangiveC10points
9. In a 200 metres race A beats B by 35 m or 7 seconds. A's time over the course is:

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Solution:
B runs 35m in 7sec
∴ B covers 200m in 735×200=40sec
B's time over the course = 40 sec
∴ A's time over the course (40 - 7) sec = 33 sec
10. A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:

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Solution:
WhenBruns25m,Aruns452mWhenBruns1000m,Aruns=(452×125×1000)m=900mBbeatsAby100 m