Practice | Hashtable

content Computer Science Arithmetic Aptitude Data Interpretation Logical Reasoning Verbal Reasoning Non-Verbal Reasoning

About About Privacy Policy

Hashtable

Home
Practice
PYQ
Mock Test
Register Free

Home Practice PYQ Mock Test Register Free

Home > Practice > Arithmetic Aptitude > Ratio and Proportion > Miscellaneous

61. Which of the following represents ab = 64?

A. 8 : a = 8 : b

B. a : 16 = 6 : 4

C. a : 8 = b : 8

D. 32 : a = b : 2

Discuss

Solution:

A = 8 : a = 8 : b ⇒ 8a = 8b ⇒ a = b.
B = a : 16 = b : 4 ⇒ 4a = 16b ⇒ a = 4b
C = a : 8 = b : 8 ⇒ 8a = 8b ⇒ b = a
D = 32 : a = b : 2 ⇒ ab =64

62. The ratio of boys and girls in a club is 3 : 2. Which of the following could be the actual number of members ?

A. 16

B. 18

C. 24

D. 25

Discuss

Solution:

The total number of members must be a multiple of the sum ratio terms.
3 + 2 = 5
and 25 is a multiple of 5

63. If m : n = 3 : 2, then (4m + 5n) : (4m - 5n) is equal to = ?

A. 4 : 9

B. 9 : 4

C. 11 : 1

D. 9 : 1

Discuss

Solution:

\begin{aligned} m : n = 3 : 2 \\ \frac{m}{n} = \frac{3}{2} \\ \Rightarrow \frac{4 m + 5 n}{4 m - 5 n} \\ \Rightarrow \frac{n (4 \frac{m}{n} + 5)}{n (4 \frac{m}{n} - 5)} \\ \Rightarrow \frac{4 \times \frac{3}{2} + 5}{4 \times \frac{3}{2} - 5} \\ \Rightarrow \frac{6 + 5}{6 - 5} \\ \Rightarrow \frac{11}{1} \\ \Rightarrow 11 : 1 \end{aligned}

64. The sum of two numbers is 40 and their difference is 4. The ratio of the numbers is = ?

A. 21 : 19

B. 22 : 9

C. 11 : 9

D. 11 : 18

Discuss

Solution:

A + B = 40
A - B = 4
∴ A = 22
B = 18
A : B = 22 : 18
= 11 : 9

65. How many sides does a regular polygon have whose interior and exterior angle are in the ratio 2 : 1 ?

A. 3

B. 5

C. 6

D. 12

Discuss

Solution:

Each exterior angle of n sided polygon is

= (\frac{360}{n})

And each interior angle of n sided polygon

\begin{aligned} = \frac{(n - 2) \times 180}{n} \\ ∴ \frac{\frac{(n - 2) \times 180}{n}}{\frac{360}{n}} = \frac{2}{1} \\ \Rightarrow \frac{(n - 2)}{2} = 2 \\ \Rightarrow n - 2 = 4 \\ \Rightarrow n = 6 \end{aligned}

66. Which of the following is the lowest ratio ?

A. 7 : 15

B. 15 : 23

C. 17 : 25

D. 21 : 39

Discuss

Solution:

\begin{aligned} \Rightarrow 7 : 15 = \frac{7}{15} = 0.466 \\ \Rightarrow 15 : 23 = \frac{15}{23} = 0.652 \\ \Rightarrow 17 : 25 = \frac{17}{25} = 0.68 \\ \Rightarrow 21 : 39 = \frac{21}{39} = 0.538 \end{aligned}

Clearly, 7 : 15 is the lowest

67. $\frac{3}{4}$ : $\frac{1}{2}$ :: 27y : ? Solve this -

A. 12y

B. 18y

C. 21y

D. 24y

Discuss

Solution:

Let the missing number be x.
Then,

\begin{aligned} = \frac{1}{3} : \frac{1}{2} :: 27 y : x \\ \Rightarrow \frac{3}{4} x = \frac{1}{2} \times 27 y \\ \Rightarrow x = \frac{27 y}{2} \times \frac{4}{3} \\ = 18 y \end{aligned}

68. Harsha is 40 years old and Ritu is 60 years old. How many years ago was the ratio of their ages is 3 : 5 ?

A. 10 years

B. 20 years

C. 37 years

D. 5 years

Discuss

Solution:

\begin{aligned} Harsha  =  40 \\ Ritu  =  60 \\ \frac{Harsha}{Ritu} = \frac{40}{60} \end{aligned}

∴ Let x years ago their ages ratio was 3 : 5

\begin{aligned} \Rightarrow \frac{40 - x}{60 - x} = \frac{3}{5} \\ \Rightarrow 200 - 5 x = 180 - 3 x \\ \Rightarrow 2 x = 20 \\ \Rightarrow x = 10 \end{aligned}

69. Two numbers are in the ratio $1 \frac{1}{2}$ : $2 \frac{2}{3}$ When each of these is increased by 15, they become in the ratio $1 \frac{2}{3}$ : $2 \frac{1}{2}$ . The greater of the numbers is = ?

A. 27

B. 36

C. 48

D. 64

Discuss

Solution:

\begin{aligned} A : B \\ \frac{3}{2} : \frac{8}{3} \end{aligned}

take L.C.M. of denominator and multiply)

\Rightarrow \frac{3}{2} \times 6 : \frac{8}{3} \times 6 = 9 x : 16 x

After adding 15 in each we get

\begin{aligned} ∴ \frac{9 x + 15}{16 x + 15} = \frac{5}{3} \times \frac{2}{5} \\ \Rightarrow \frac{9 x + 15}{16 x + 15} = \frac{2}{3} (cross multiply) \\ \Rightarrow 27 x + 45 = 32 x + 30 \\ \Rightarrow 5 x = 15 \\ \Rightarrow x = 3 \\ ∴ Smaller number \\ = 9 \times 3 =  27 \\ Greater number \\ =  16 \times 3 =  48 \end{aligned}

70. A sum of Rs. 1240 is distributed among A, B and C such that the ratio of amount received by A and B is 6 : 5 and that of B and C is 10 : 9 respectively. Find the share of C ?

A. Rs. 480

B. Rs. 360

C. Rs. 400

D. Rs. 630

Discuss

Solution:

Given,A : B = 6 : 5
B : C = 10 : 9
A : B = 6 : 5 (multiply with 2)
i.e. A : B = 12 : 10
∴ A : B : C = 12 : 10 : 9
⇒ 12x + 10x + 9x = 1280
⇒ x = 40
∴ Share of C = 9 × 40 = 360

1 2 3 4 5 6 7 8 9 10

Sign up for our newsletter

Are you passionate about opportunities in the realm of Computer Science within the government sector? Don't miss out on crucial updates, job openings, and career prospects tailored specifically straight to your inbox.

Email address

By subscribing, you agree with our Terms of Service and Privacy Policy.

Resources

Practice PYQ Mock Test

Company

About us Contact us Privacy policy Terms of service

Hashtable