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61. What was the day of the week on 16th August, 1947?
Counting of odd days:
1600 years have 0 odd day. 300 years have 1 odd day.
47 years = (11 leap years + 36 ordinary years)
= [(11 x 2) + (36 x 1) ] odd days
= 58 odd days
= 2 odd days
Jan Feb Mar Apr May Jun Jul Aug
= 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15
= 227 days
= (32 weeks + 3 days)
= 3,
Total number of odd days
= (0 + 1 + 2 + 3) odd days
= 6 odd days.
Hence, the required day was 'Saturday'.
Solution:
15th August, 1947 = (1946 years + Period from 1st Jan., 1947 to 15th )Counting of odd days:
1600 years have 0 odd day. 300 years have 1 odd day.
47 years = (11 leap years + 36 ordinary years)
= [(11 x 2) + (36 x 1) ] odd days
= 58 odd days
= 2 odd days
Jan Feb Mar Apr May Jun Jul Aug
= 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15
= 227 days
= (32 weeks + 3 days)
= 3,
Total number of odd days
= (0 + 1 + 2 + 3) odd days
= 6 odd days.
Hence, the required day was 'Saturday'.
62. Prove that any date in March of a year is the same day of the week corresponding date in November that year.
March April May June July Aug. Sept. Oct.
31 + 30 + 31 + 30 + 31 + 31 + 30 + 31
= 241 days
= 35 weeks
= 0 odd day
Number of odd days during this period = 0.
Thus, 1st March of an year will be the same day as 1st November of that year. Hence, the result follows
Solution:
We will show that the number of odd days between last day of February and last day of October is zero.March April May June July Aug. Sept. Oct.
31 + 30 + 31 + 30 + 31 + 31 + 30 + 31
= 241 days
= 35 weeks
= 0 odd day
Number of odd days during this period = 0.
Thus, 1st March of an year will be the same day as 1st November of that year. Hence, the result follows
63. If today is Saturday, what will be the day 350 days from now ?
So it will be a Saturday.
Solution:
350 days = = 50 weeks, i.e No odd days,So it will be a Saturday.
64. The calendar for the year 1988 is same as which upcoming year ?
Here 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.
Solution:
We already know that the calendar after a leap year repeats again after 28 years.Here 1988 is a Leap year, then the same calendar will be in the year = 1988 + 28 = 2016.
65. Given that on 9th August 2016 is Saturday. What was the day on 9th August 1616 ?
Thus, if 9th August 2016 is Saturday, before 400 years
i.e., on 9th August 1616 has to be Saturday.
Solution:
We know that, After every 400 years, the same day occurs.Thus, if 9th August 2016 is Saturday, before 400 years
i.e., on 9th August 1616 has to be Saturday.
66. Second & fourth Saturdays and every Sunday is a holiday. How many working days will be there in a month of 31 days beginning on a Friday ?
Sundays = 3rd, 10th, 17th, 24th, 31st
⇒ Total Sundays = 5
Every second & fourth Saturday is holiday. 2nd & 4th Saturday in every month = 2
Total days in the month = 31
Total working days = 31 - (5 + 2) = 24 days.
Solution:
Given that the month begins on a Friday and has 31 daysSundays = 3rd, 10th, 17th, 24th, 31st
⇒ Total Sundays = 5
Every second & fourth Saturday is holiday. 2nd & 4th Saturday in every month = 2
Total days in the month = 31
Total working days = 31 - (5 + 2) = 24 days.
67. On 17th March, 1997 Monday falls. What day of the week was it on 17th March, 1996?
So, the day on 17th March, 1997 will be 1 day beyond the day on 17th March,1996.
Here 17th March, 1997 is Monday. So, 17th March, 1996 is Sunday.
Solution:
The year 1996 is a leap year. So, it has 2 odd days. But 17th March comes after 29th February.So, the day on 17th March, 1997 will be 1 day beyond the day on 17th March,1996.
Here 17th March, 1997 is Monday. So, 17th March, 1996 is Sunday.
68. Which year has 366 days?
So, 1200 has 366 days.
Solution:
When a century year leaves a remainder 0, when divided by 400 then it is a leap year (366 days).So, 1200 has 366 days.
69. What is 90 days from today?
(Hints : Today is 20th January 2017, Sunday)
In january, we have 31 days
February - 28 days (Non leap year)
March - 31 days
April - 30 days
⇒ Remaining days = 31 - 20 = 11 in Jan
11 in Jan + 28 in Feb + 31 in Mar = 11 + 28 + 31 = 70 days
More 20 days to complete 90 days ⇒ upto 20th April
Therefore, after 90 days from today i.e, 20th Jan 2017 is 20th Apr 2017.
Now, the day of the week will be
⇒ Remainder '6'
As the day starts with '0' on sunday
6 ⇒ Saturday.
Required day is 20th April, Saturday.
(Hints : Today is 20th January 2017, Sunday)
Solution:
Given Today is 20th January 2017, SundayIn january, we have 31 days
February - 28 days (Non leap year)
March - 31 days
April - 30 days
⇒ Remaining days = 31 - 20 = 11 in Jan
11 in Jan + 28 in Feb + 31 in Mar = 11 + 28 + 31 = 70 days
More 20 days to complete 90 days ⇒ upto 20th April
Therefore, after 90 days from today i.e, 20th Jan 2017 is 20th Apr 2017.
Now, the day of the week will be
⇒ Remainder '6'
As the day starts with '0' on sunday
6 ⇒ Saturday.
Required day is 20th April, Saturday.
70. On 24th Nov, 2007 Thursday falls. What day of the week was it on 10th Nov, 2006 ?
So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24
th Nov, 2006.
But, 24th Nov, 2007 is Thursday.
24 - 10 = 14 days.
Therefore, 2 weeks ago it is same day.
Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.
Solution:
The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24
th Nov, 2006.
But, 24th Nov, 2007 is Thursday.
24 - 10 = 14 days.
Therefore, 2 weeks ago it is same day.
Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.