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81. In a year, Holi was enjoyed on 6th March 9 AM and Deepawali (Diwali) was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ?
there are 250 days and
Thus 250 x 24 hours
So from Mar 6th 9AM to Nov 11th 8PM, there will be
250 x 24 + 11
hours = 6011 hrs.
Solution:
From March 6th to November 11th,there are 250 days and
Thus 250 x 24 hours
So from Mar 6th 9AM to Nov 11th 8PM, there will be
250 x 24 + 11
hours = 6011 hrs.
82. What was the day on 9th May, 2001?
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 9) = 129 days
129 days = (18 weeks + 3 day) = 3 odd day
Total number of odd days = (0 + 0 + 3 ) = 3 odd day
Given day is Wednesday
Solution:
9th May, 2001 = (2000 years + Period from 1.1.2001 to 9.5.2001)Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 9) = 129 days
129 days = (18 weeks + 3 day) = 3 odd day
Total number of odd days = (0 + 0 + 3 ) = 3 odd day
Given day is Wednesday
83. If 4th december 1999 is Monday then what day is 3rd january 2000 ?
there is a difference of 30 days
Number of odd days = = 2 odd days
Then no. of odd days = 2 ⇒ tuesday and wednesday (from monday)
Hence on 3rd january it is wednesday.
Solution:
Here from 4th December 1999 to 3rd January 2000,there is a difference of 30 days
Number of odd days = = 2 odd days
Then no. of odd days = 2 ⇒ tuesday and wednesday (from monday)
Hence on 3rd january it is wednesday.
84. Which calendar was used again in the year 1856?
NOTE: When remainder is 0, 28 is subtracted to the given year to get the result.
So, 1856 - 28 = 1828
Solution:
Given year 1856, when divided by 4 leaves a remainder of 0.NOTE: When remainder is 0, 28 is subtracted to the given year to get the result.
So, 1856 - 28 = 1828
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