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41. A tradesman fixed his selling price of goods at 30% above the cost price. He sells half the stock at this price, one-quarter of his stock at a discount of 15% on the original selling price and rest at a discount of 30% on the original selling price. Find the gain percentage altogether?
Now, revenue
Solution:
Let CP = 100; then marked price = 130;Now, revenue
42. A dishonest dealer marks up the price of his goods by 20% and gives a discount of 10% to the customer. Besides, he also cheats both his supplier and his buyer by 100 grams while buying or selling 1 kilogram. Find the percentage profit earned by the shopkeeper?
He buys 1100 gram instead of 1000 gram.
Suppose he bought 1100 grams for Rs. 1000.
While selling,
He sells only 900 grams when he takes the money for 1 kg.
Now, according to the problem,
he sells at a 8% profit (20% markup, 10% discount).
Hence, his selling price is Rs. 1080 for 900 grams.
Now,
1100 grams for Rs. 1000
Hence, 1188 grams for Rs. 1080
Selling: 900 grams for Rs. 1080
Hence, % profit = × 100 = 32%
(using goods left by goods sold formula).
Solution:
While buying,He buys 1100 gram instead of 1000 gram.
Suppose he bought 1100 grams for Rs. 1000.
While selling,
He sells only 900 grams when he takes the money for 1 kg.
Now, according to the problem,
he sells at a 8% profit (20% markup, 10% discount).
Hence, his selling price is Rs. 1080 for 900 grams.
Now,
1100 grams for Rs. 1000
Hence, 1188 grams for Rs. 1080
Selling: 900 grams for Rs. 1080
Hence, % profit = × 100 = 32%
(using goods left by goods sold formula).
43. Ajay bought a motor cycle for Rs. 50,000. 2 years later he sold it to Vijay at 10% less of the cost price. Vijay spend 5% of the purchasing price on its maintenance. Later Vijay displayed the sale price of his motorcycle Rs. 50,000. Chetan wanted to purchase it at 15% discount but Vijay gave him two successive discounts of 10% and 5% instead of 15% in one time. What is the actual discount availed by Chetan?
Net discount = 100 - 85.5 = 14.5%
Solution:
100 --- 10%↓(1st discount) → 90 --- 5%↓ → 85.5Net discount = 100 - 85.5 = 14.5%
44. A trader sells goods to a customer at a profit of k% over the cost price, besides it he cheats his customer by giving 880 g only instead of 1 kg. Thus his overall profit percentage is 25%. Find the value of k?
→ k = 100
Thus,
Net % profit = = 10%
Solution:
% Profit = = → k = 100
Thus,
Net % profit = = 10%
45. A retailer increase the selling price by 25% due to which his profit percentage increase from 20% to 25%. What is the percentage increase in cost price ?
120 (SP) --- 25%↑ → 150 (New SP)
Let x be the new Cost price
Selling Price = 150
x × 1.25 = 150
x = 120
% change = = 20%
Solution:
100 (Initial CP) --- 20%↑ (initial profit) → 120(SP)120 (SP) --- 25%↑ → 150 (New SP)
Let x be the new Cost price
Selling Price = 150
x × 1.25 = 150
x = 120
% change = = 20%
46. A watch costing Rs. 120 was sold at a loss of 15%. At what price was it sold?
Mental work:
10% of Rs. 120 = 12
5% of Rs 120 = 6
Solution:
120 (CP) --- 15% ↓(loss) → 102 (SP)Mental work:
10% of Rs. 120 = 12
5% of Rs 120 = 6
47. The cost of setting up a magazine is Rs. 2800. The cost of paper and ink etc is Rs. 80 per 100 copies and printing cost is Rs. 160 per 100 copies. In last month 2000 copies were printed but only 1500 copies could be sold at Rs. 5 each. Total 25% profit on the sale price was realized. There is one more resource of income from magazine which is advertising. What sum of money obtained from the advertising in magazine?
Paper etc = Rs. 1600
Printing cost = Rs. 3200
Total cost = Rs. 7600
Total sale price = 1500 × 5 = 7500
Let amount obtained from advertising be x then,
(7500 + x) - 7600 = 25% of 7500
x = 1975
Solution:
Set up cost = Rs. 2800Paper etc = Rs. 1600
Printing cost = Rs. 3200
Total cost = Rs. 7600
Total sale price = 1500 × 5 = 7500
Let amount obtained from advertising be x then,
(7500 + x) - 7600 = 25% of 7500
x = 1975
48. A person bought a certain quantity of rice at the rate of Rs. 150/quintal. 10% of the rice was spoiled. At what rate(per quintal) should he sell the remaining rice to earn 20% profit.
10% is spoiled so he now have to sell of 90 kg remaining).
But he has to make a profit of 20%,so he will sell
90kg for Rs. 180
This means his selling price is Rs. 200 per quintal.
Solution:
Suppose he buy 1 quintal of Rice in Rs.150.10% is spoiled so he now have to sell of 90 kg remaining).
But he has to make a profit of 20%,so he will sell
90kg for Rs. 180
This means his selling price is Rs. 200 per quintal.
49. A trader sells two brands of petrol; one is Extra Premium and other one is speed. He mixes 12 litres Extra Premium with 3 litres of speed and by selling this mixture at the price of Extra Premium he gets the profit of 9.09. If the price of Extra Premium Rs. 48 per litre, then the price of Speed is:
= (CP + 9.09% of CP)
48 = of CP
CP = 44
No, using Alligation method,
4 : 1Thus,
X = 44
Thus, the price of speed brand is Rs. 28/litre.
Solution:
Selling price mix EP,= (CP + 9.09% of CP)
48 = of CP
CP = 44
No, using Alligation method,
4 : 1Thus,
X = 44
Thus, the price of speed brand is Rs. 28/litre.
50. Kamal bought a house, whose sale price was Rs. 8 lakh. He availed 20% discount as an early bird offer and then 10% discount due to cash payment. After that he spent 10% of the cost price in interior decoration and lawn of the house. At what price should he sell the house to earn a profit of 25%?
100 == 20% ↓(discount) ⇒ 80 == 10%↓ (discount) ⇒ 72(CP) == 10%↑ (interior) ⇒ 79.2(Total CP)
Now, selling price would be 25% above the Total cost price.
SP = 79.2 + 25% of 79.2
SP = 99
Now, On comparing,
100 ⇒ 800000
99 ⇒ ⇒ 7,92,000
So,
SP = Rs. 7,92,000
Solution:
Let the marked price be 100100 == 20% ↓(discount) ⇒ 80 == 10%↓ (discount) ⇒ 72(CP) == 10%↑ (interior) ⇒ 79.2(Total CP)
Now, selling price would be 25% above the Total cost price.
SP = 79.2 + 25% of 79.2
SP = 99
Now, On comparing,
100 ⇒ 800000
99 ⇒ ⇒ 7,92,000
So,
SP = Rs. 7,92,000