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1. A right triangle with sides 3 cm, 4 cm and 5 cm is rotated the side of 3 cm to form a cone. The volume of the cone so formed is:

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Solution:
Volume and Surface Area mcq solution image
Clearly,We have r=3cmandh=4cmVolume=13πr2h=(13×π×32×4)cm3=12πcm3
2. In a shower, 5 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:

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Solution:
1hectare=10000m2So,Area=(1.5×10000)m2=15000m2Depth=5100m=120mVolume=(Area×Depth)=(15000×120)m3=750m3
3. A hall is 15 m long and 12 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:

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Solution:
2(15+12)×h=2(15×12)h=18027m=203mVolume=(15×12×203)m3=1200m3
4. 66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be:

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Solution:
Letthelengthofthewirebe hRadius=12mm=120cm.Then,227×120×120×h=66h=66×20×20×722=8400cm=84meters
5. A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weights 8 g/cm3, then the weight of the pipe is:

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Solution:
Externalradius=4cmInternalradius=3cmVolumeofiron=(227×[(4)2(3)2]×21)cm3=(227×7×1×21)cm3=462cm3Weightofiron=(462×8)gm=3696gm=3.696kg
6. A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is:

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Solution:
Volume of water displaced
= (3 x 2 x 0.01) m3
= 0.06 m3.
∴ Mass of man = Volume of water displaced x Density of water
= (0.06 x 1000) kg
= 60 kg.
7. 50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 m3, then the rise in the water level in the tank will be:

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Solution:
TotalVolumeofwaterdisplaced=(4×50)m3=200m3Riseinwaterlevel=(20040×20)m=0.25m=25cm
8. The slant height of a right circular cone is 10 m and its height is 8 m. Find the area of its curved surface.

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Solution:
l=10mh=8mSo,r=l2h2=(10)282=6mCurvedsurfaceareaπrl=(π×6×10)m2=60πm2
9. A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:

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Solution:
Areaofthewetsurface=[2(lb+bh+lh)lb]=2(bh+lh)+lb=[2(4×1.25+6×1.25)+6×4]m2=49m2
10. A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is:

Discuss
Solution:
Clearly, l = (48 - 16)m = 32 m,
b = (36 -16)m = 20 m,
h = 8 m.
∴ Volume of the box
= (32 x 20 x 8) m3
= 5120 m3