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Home > Practice > Arithmetic Aptitude > True Discount > Miscellaneous

51. If a person purchases a shirt, he gets 6% discount. However, if he purchases two shirts, he gets 5% on the first and 8% on the second. If the price paid by the person for two shirts is Rs. 925, then what will be the marked price of each shirts ?

A. Rs. 494

B. Rs. 550

C. Rs. 528

D. Rs. 500

Discuss

Solution:

Let marked price = 100x, then by statement
95x + 92x → selling price of both

\begin{aligned} \Rightarrow 187 x \to 925 \\ \Rightarrow x \to \frac{925}{187} = 4.94 \\ Marked price \\ =  4 .94 \times 100 \\ =  Rs . 494 \end{aligned}

52. The selling price of an article is Rs. 1920 and the discount given is 4%. The marked price of the article is = ?

A. Rs. 2400

B. Rs. 2000

C. Rs. 1600

D. Rs. 1200

Discuss

Solution:

Let marked price = Rs. x
Selling price after 4% discount

=  Rs . \frac{96 x}{100}

\begin{aligned} ∴ \frac{96 x}{100} = 1920 \\ \Rightarrow x = \frac{1920 \times 100}{96} \\ \Rightarrow x = Rs. 2000 \end{aligned}

53. If an electricity bill is paid before due date, one gets a reduction of 4% on the amount of the bill. By paying the bill before due date a person got a reduction of Rs. 13. The amount of his electricity bill was = ?

A. Rs. 125

B. Rs. 225

C. Rs. 325

D. Rs. 425

Discuss

Solution:

Let the amount of bill = Rs. x
According to the question,

\begin{aligned} \Rightarrow \frac{4 x}{100} = 13 \\ x = \frac{13 \times 100}{4} \\ x = Rs . 325 \end{aligned}

Alternate :
Let the amount of bill = 100 units
4% of 100 units = 4 units

\begin{aligned} ∴ 4 units = 13 \\ \Rightarrow 1 unit = \frac{13}{4} \\ \Rightarrow 100 units  = \frac{13}{4} \times 100 \\ = Rs . 325 \end{aligned}

54. The single discount equal to three consecutive discounts of 10%, 12% and 5% ?

A. 35%

B. 32%

C. 24.76%

D. 30%

Discuss

Solution:

Let the marked price Rs. 100

\begin{aligned} Final selling price \\ = 100 \times \frac{90}{100} \times \frac{88}{100} \times \frac{95}{100} \\ =  Rs . 75 .24 \\ Net discount \\ = (100 - 75.24) \\ =  24 .76 % \end{aligned}

Alternate :
Single equivalent discount for 10% and 12%

\begin{aligned} = (10 + 12 - \frac{10 \times 12}{100}) % \\ = 20.8 % \end{aligned}

Single equivalent discount for 20.8% and 5%

\begin{aligned} = (20.8 + 5 - \frac{20.8 \times 5}{100}) % \\ = 24.76 % \end{aligned}

55. The difference between discount of 35% and two successive discount of 20% on a certain bill was 22, the amount of the bill is = ?

A. Rs. 200

B. Rs. 220

C. Rs. 1100

D. Rs. 2200

Discuss

Solution:

1st discount = 35%
Single equivalent discount of 20% each

\begin{aligned} = (20 + 20 - \frac{20 \times 20}{100}) % \\ = 36 % \\ Difference \\ = (36 % - 35 %) \\ = 1 % \end{aligned}

Let the amount of the bill Rs. x

\begin{aligned} ∴ \frac{1}{100} x = 22 \\ x = Rs . 2200 \end{aligned}

56. A owes B, Rs. 1573 payable $1 \frac{1}{2}$ years hence. Also B owes A, Rs. 1444.50 payable 6 months hence. If they want to settle the account forthwith, keeping 14% as the rate of interest, then who should pay and how much ?

A. A Rs. 28.50

B. B Rs. 37.50

C. A Rs. 50

D. B Rs. 50

Discuss

Solution:

A owes = P.W. of Rs. 1573 due

\frac{3}{2}

years hence

\begin{aligned} = Rs . [\frac{1573 \times 100}{100 + (14 \times \frac{3}{2})}] \\ = Rs . (\frac{1573 \times 100}{121}) \\ = Rs . 1300. \end{aligned}

B owes = P.W. of Rs. 1444.50 due 6 months hence

\begin{aligned} = Rs . [\frac{1444.50 \times 100}{100 + (14 \times \frac{1}{2})}] \\ = Rs . (\frac{1444.50 \times 100}{107}) \\ = Rs . 1350. \\ ∴ B must pay Rs . 50 to A \end{aligned}

57. The marked price of the a watch is Rs. 1600. The shopkeeper gives successive discount of 10% and x% to the customer. It the customer pays Rs. 1224 for the watch, the value of x is = ?

A. 5%

B. 10%

C. 15%

D. 20%

Discuss

Solution:

Marked price of watch = Rs. 1600
After 1st discount of 10%

\begin{aligned} =  1600 \times \frac{90}{100} \\ =  Rs . 1440 \end{aligned}

Customer pays (final selling price) = Rs. 1224

\begin{aligned} \frac{x}{100} \times 1440 = (1440 - 1224) \\ \frac{x}{100} \times 1440 = 216 \\ x = \frac{216 \times 100}{1440} \\ x = 15 % \end{aligned}

58. A single discount equivalent to discount series 20% , 20% and 10% is = ?

A. 50%

B. 48.4%

C. 42.4%

D. 40.4%

Discuss

Solution:

Single equivalent discount for 20% and 20%

\begin{aligned} = 20 + 20 - \frac{20 \times 20}{100} \\ = 40 - 4 \\ = 36 % \end{aligned}

Single equivalent discount for 36% and 10%

\begin{aligned} = 36 + 10 - \frac{36 \times 10}{100} \\ = 46 - 3.6 \\ = 42.4 % \end{aligned}

59. The single discount equivalent to the discount series of 20%, 10% and 5% is = ?

A. 11.66%

B. 31.6%

C. 35.66Z%

D. 32%

Discuss

Solution:

Single equivalent discount for 20% and 10%

\begin{aligned} = 20 + 10 - \frac{20 \times 10}{100} \\ = 30 - 2 \\ = 28 % \end{aligned}

Single equivalent discount for 28% and 5%

\begin{aligned} = 28 + 5 - \frac{28 \times 5}{100} \\ = 33 - 1.4 \\ = 31.6 % \end{aligned}

60. Successive discount of p% and q% on the catalogue price of an article is equivalent to a single discount of = ?

A. $(p - q - \frac{p q}{100}) %$

B. $(p + q - \frac{p q}{100}) %$

C. $(p - q + \frac{p q}{100}) %$

D. $(p + q + \frac{p q}{100}) %$

Discuss

Solution:

= (p - q + \frac{p q}{100}) %

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