Practice | Hashtable

91. Study the following table which shows the amount of money invested (Rupees in crore) in the core infrastructure areas of two districts. A and B of a State, and answer the below five questions.

District A District B

Core Area 1995 1996 1995 1996

Electricity
Chemical
Thermal
Solar
Nuclear 815.2
389.5
632.4
468.1
617.9 1054.2
476.7
565.9
589.6
803.1 2065.8
745.3
1232.7
1363.5
1674.3 2365.1
986.4
1026.3
1792.1
2182.1

Total 2923.1 3489.5 7081.6 8352.0

If the total investment in district B shows the same rate of increase in 1997, as it had shown from 1995 to 1996, what approximately would be the total investment in B in 1997?

A. Rs. 10020 crore

B. Rs. 9850 crore

C. Rs. 8540 crore

D. Rs. 9170 crore

Discuss

Solution:

Difference of 1995 & 1996
= 8352 - 7081.6
= 1270.4
Increase % =

\frac{1270.4}{7081.6}

× 100
= 17.9% (Approx)
B investment in 1997
=

\frac{117.9}{100}

× 8352
= Rs. 9850 crore (Approx)

92. Study the following table which shows the amount of money invested (Rupees in crore) in the core infrastructure areas of two districts. A and B of a State, and answer the below five questions.

District A District B

Core Area 1995 1996 1995 1996

Electricity
Chemical
Thermal
Solar
Nuclear 815.2
389.5
632.4
468.1
617.9 1054.2
476.7
565.9
589.6
803.1 2065.8
745.3
1232.7
1363.5
1674.3 2365.1
986.4
1026.3
1792.1
2182.1

Total 2923.1 3489.5 7081.6 8352.0

The total investment in electricity and thermal energy in 1995, in these two districts A and B formed approximately what percent of the total investment made in that year?

A. 47%

B. 41%

C. 52%

D. 55%

Discuss

Solution:

Investment of A & B in electricity & thermal energy in 1995
= 815.2 + 2065.8 + 632.4 + 1232.7
= 4746.1
Total investment of A & B in 1995
= 2923.1 + 7081.6
= 10004.7
∴ Required percentage
=

\frac{4746.1}{10004.7}

× 100
= 47% (Approx)

93. Study the following table which shows the amount of money invested (Rupees in crore) in the core infrastructure areas of two districts. A and B of a State, and answer the below five questions.

District A District B

Core Area 1995 1996 1995 1996

Electricity
Chemical
Thermal
Solar
Nuclear 815.2
389.5
632.4
468.1
617.9 1054.2
476.7
565.9
589.6
803.1 2065.8
745.3
1232.7
1363.5
1674.3 2365.1
986.4
1026.3
1792.1
2182.1

Total 2923.1 3489.5 7081.6 8352.0

Approximately how many times was the total investment in 1995 and 1996 in district B was that of total investment of district A in the same years?

A. 2.8

B. 2.4

C. 1.7

D. 1.9

Discuss

Solution:

Total investment of A
= 2923.1 + 3489.5
= 6412.6
Total investment of B
= 7081.6 + 8352
= 15433.6
∴ Times =

\frac{15433.6}{6412.6}

= 2.4 (Approx)

94. Study the following table which shows the amount of money invested (Rupees in crore) in the core infrastructure areas of two districts. A and B of a State, and answer the below five questions.

District A District B

Core Area 1995 1996 1995 1996

Electricity
Chemical
Thermal
Solar
Nuclear 815.2
389.5
632.4
468.1
617.9 1054.2
476.7
565.9
589.6
803.1 2065.8
745.3
1232.7
1363.5
1674.3 2365.1
986.4
1026.3
1792.1
2182.1

Total 2923.1 3489.5 7081.6 8352.0

By approximately what percent was the total investment in the two districts A and B More in 1996 as compared to 1995?

A. 18%

B. 24%

C. 21%

D. 14%

Discuss

Solution:

Total investment of A & B in 1995
= 2923.1 + 7081.6
= Rs. 10004.7
Total investment of A & B in 1996
= 3489.5 + 8352
= Rs. 11841.5
∴ Increase %

\begin{aligned} = \frac{11841.5 - 10004.7}{10004.7} \times 100 \\ = \frac{1836.8}{10004.7} \times 100 \\ = 18 % (Approx) \end{aligned}

95. Study the following table which shows the amount of money invested (Rupees in crore) in the core infrastructure areas of two districts. A and B of a State, and answer the below five questions.

District A District B

Core Area 1995 1996 1995 1996

Electricity
Chemical
Thermal
Solar
Nuclear 815.2
389.5
632.4
468.1
617.9 1054.2
476.7
565.9
589.6
803.1 2065.8
745.3
1232.7
1363.5
1674.3 2365.1
986.4
1026.3
1792.1
2182.1

Total 2923.1 3489.5 7081.6 8352.0

In district B, the investment in which area in 1996 did show the highest percentage increase over the investment in that area in 1995?

A. Chemical

B. Solar

C. Electricity

D. Nuclear

Discuss

Solution:

\begin{aligned} Chemical % \\ = \frac{986.4 - 745.3}{745.3} \times 100 \\ = \frac{241.1 \times 100}{745.3} \\ = 32.34 % \\ Solar % \\ = \frac{1792.1 - 1363.5}{1363.5} \times 100 \\ = \frac{428.6}{1363.5} \times 100 \\ = 31.4 % \\ Electricity % \\ = \frac{2365.1 - 2065.8}{2065.8} \times 100 \\ = \frac{299.3}{2064.8} \times 100 \\ = 14.4 % \\ Nuclear % \\ = \frac{2182.1 - 1674.3}{1674.3} \times 100 \\ = \frac{507.8}{1674.3} \times 100 \\ = 30.3 % \end{aligned}

So the highest percentage is in Chemical area

	District A		District B
Core Area	1995	1996	1995	1996
Electricity Chemical Thermal Solar Nuclear	815.2 389.5 632.4 468.1 617.9	1054.2 476.7 565.9 589.6 803.1	2065.8 745.3 1232.7 1363.5 1674.3	2365.1 986.4 1026.3 1792.1 2182.1
Total	2923.1	3489.5	7081.6	8352.0