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111. 3, 4, 7, 7, 13, 13, 21, 22, 31, 34, ?
I. 3, 7, 13, 21, 31, ? and II. 4, 7, 13, 22, 34
The pattern in I is + 4, + 6, + 8, + 10,.....
The pattern in II is + 3, + 6, + 9, + 12,.....
So, missing term = 31 + 12 = 43.
Solution:
The given sequence is a combination of two series :I. 3, 7, 13, 21, 31, ? and II. 4, 7, 13, 22, 34
The pattern in I is + 4, + 6, + 8, + 10,.....
The pattern in II is + 3, + 6, + 9, + 12,.....
So, missing term = 31 + 12 = 43.
112. 198, 194, 185, 169, ?
So, missing pattern = 169 - 52 = 169 - 25 = 144.
Solution:
The pattern is - 4, - 9, - 16,.....i.e. - 22, - 32, - 42,.....So, missing pattern = 169 - 52 = 169 - 25 = 144.
113. 2, 3, 5,7,11,?, 17
term is the prime number after 11, which is 13.
Solution:
Clearly, the given series consists of prime numbers starting from 2. So, the missingterm is the prime number after 11, which is 13.
114. 6, 12, 21, ?, 48
So, missing term = 21 + 12 = 33.
Solution:
The pattern is + 6, + 9, + 12, + 15, .....So, missing term = 21 + 12 = 33.
115. Which term of the series 5, 10, 20, 40, ..... is 1280?
So, the series is a G.P. in which a = 5 and r = 2.
Let 1280 be the rath term of the series.
Then, 5x2n-1 = 1280 ⇔ 2n-1 = 256 = 28 ⇔ n - 1 = 8 ⇔ n = 9.
Solution:
Clearly, 5 x 2 = 10, 10 x 2 = 20, 20 x 2 = 40,.....So, the series is a G.P. in which a = 5 and r = 2.
Let 1280 be the rath term of the series.
Then, 5x2n-1 = 1280 ⇔ 2n-1 = 256 = 28 ⇔ n - 1 = 8 ⇔ n = 9.
116. 2, 5, 9, ?, 20, 27
So, missing term = 9 + 5 = 14.
Solution:
The pattern is + 3, + 4, + 5, + 6,.....So, missing term = 9 + 5 = 14.
117. 2, 3, 3, 5, 10, 13, ?, 43, 172, 177
So, missing term = 13 x 3 = 39.
Solution:
The pattern is + 1, x 1, + 2, x 2, + 3, x 3, + 4, x 4, + 5.So, missing term = 13 x 3 = 39.
118. 9, 27, 31, 155, 161, 1127, ?
So, missing term = 1127 + 8 = 1135.
Solution:
The pattern is x 3, + 4, x 5, + 6, x 7,.....So, missing term = 1127 + 8 = 1135.
119. 2, 1, 2, 4, 4, 5, 6, 7, 8, 8, 10, 11, ?
I. 1st, 4th, 7th, 10th, 13th terms i.e. 2, 4, 6, 8, ?
II. 2nd, 5th, 8th, 11th terms i.e. 1, 4, 7, 10
III. 3rd, 6th, 9th, 12th terms i.e. 2, 5, 8, 11
Clearly, I consists of consecutive even numbers. So, the missing term is 10.
Solution:
The given sequence is a combination of three series :I. 1st, 4th, 7th, 10th, 13th terms i.e. 2, 4, 6, 8, ?
II. 2nd, 5th, 8th, 11th terms i.e. 1, 4, 7, 10
III. 3rd, 6th, 9th, 12th terms i.e. 2, 5, 8, 11
Clearly, I consists of consecutive even numbers. So, the missing term is 10.
120. Which of the following will not be a number of the series 1, 8, 27, 64, 125,.....?
any natural number.
Solution:
The given series consists of cubes of natural numbers only. 256 is not the cube ofany natural number.