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221. _ bcc _ ac _ aabb _ ab _ cc.
bbccaa / ccaabb / aabbcc.
The pairs of the letters are moving in cyclic order.
Solution:
The series is,bbccaa / ccaabb / aabbcc.
The pairs of the letters are moving in cyclic order.
223. Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it ?
_ stt _ tt _ tts _
_ stt _ tt _ tts _
Solution:
The series is tst/tst/tst/tst. Thus, the pattern 'tst' is repeated.
224. Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it ?
gfe _ ig _ eii _ fei _ gf_ ii
gfe _ ig _ eii _ fei _ gf_ ii
Solution:
The series is gfeii/gfeii/gfeii/gfeii. Thus, the pattern 'gfeii' is repeated.
225. Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it ?
_ a _ b _ abaa _ bab _ abb
_ a _ b _ abaa _ bab _ abb
Solution:
The series is baa/bba/baa/bba/baa/bb. Thus, the pattern baa/bba is repeated.
226. Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it ?
abca _ bcaab _ ca _ bbc _ a
abca _ bcaab _ ca _ bbc _ a
Solution:
The series is abc/aabc/aabbc/aabbcc/a.
227. Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it ?
_ tu _ rt _ s _ _ usrtu _
_ tu _ rt _ s _ _ usrtu _
Solution:
The series rtus/rtus/rtus/rtus. Thus, the pattern 'rtus' is repeated.
228. Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it ?
_ _aba _ _ ba _ ab
_ _aba _ _ ba _ ab
Solution:
The series is ab/ab/ab/ab/ab/ab. Thus, the pattern 'ab' is repeated.
229. Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it ?
c _ bbb _ _ abbbb _ abbb _
c _ bbb _ _ abbbb _ abbb _
Solution:
The series is cabbbb/cabbbb/cabbbb. Thus, the pattern 'cabbbb' is repeated.
230. Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it ?
_ bbca _ bcca _ ac _ a _ cb
_ bbca _ bcca _ ac _ a _ cb
Solution:
The series is abbc/ac/bcca/ba/caab/cb.