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271. Choose the correct order of the given alternative : m n o n o p q o p q r s _ _ _ _ _

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Solution:
The series is mno/nopq/opqrs/pqrst.
272. Choose the correct order of the given alternative : _ bca _ cca _ ca _ b _ c

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Solution:
The series is bbca/bcca/bcaa/bbc.
273. Choose the correct order of the given alternative : ccbab _ caa _ bccc _ a _

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Solution:
The series is ccba/bbca/aabc/ccba/b.
274. Choose the correct order of the given alternative : b _ b _ bb _ _ bbb _ bb _ b

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Solution:
The series is babb/bbab/bbba/bbbb.. Thus, in each sequence, 'a' moves one step forward and 'b' takes its place and finally in the fourth sequence, it is eliminated.
275. Choose the correct order of the given alternative : abc _ d _ bc _ d _ b _ cda

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Solution:
The series is abcdd/abccd/abbcd/a.
276. Choose the correct order of the given alternative : a _ c _ abb _ a _ bc _ bc _ ab

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Solution:
The series is abccab/bcaabc/abccab.
Thus, the pattern 'abccab/bcaabc' is repeated.
277. Choose the correct order of the given alternative : a _ bc _ c _ abb _ bca _

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Solution:
The series is aabcc/ccabb/bbcaa.
278. Choose the correct order of the given alternative : aa _ aaa _ aaaa _ aaaa_ b

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Solution:
The series is aab/aaab/aaaab/aaaaab.
Thus, the number of a's increasing by one in the successive sequence,
279. Choose the correct order of the given alternative : XWC _ TS20 _ P12 _ L15K _ P _ GS7

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Solution:
From the alternatives, it is clear that the series can be divided in to 5 groups of four terms each - each group comprising of three letters and a number.
XWC _ /TS20 _/P12 _ L/15K _ P/_ GS7
Observing the above series, we find that each group consists of two consecutive letters and the number represents the position of one of these letters in the English alphabet.
So, 1 st missing term must be the number corresponding to W or X i.e., 23 or 24.
280. Choose the correct order of the given alternative : D _ 6EGP _ HJ _ 12KMB15 _

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Solution:
From the alternatives, it is clear that the series can be divided in to 4 groups of four terms each - each group comprising of three letters and a number at the third place.
D _ 6E/GP _ H/J _ 12K/MB15 _
Studying the pairs 6E and 12K, we find in each group the number is one more than the number represents the position of the letter at the forth place, in the English alphabet.
Thus, putting A = 1, B = 2, ......y = 25, Z = 26,
We have,
2nd missing tertm = H + 1 = 8 + 1 = 9;
4th missing term = 15 - 1= 14th letter = N
Thus , the 2nd and 4th missing terms are 9 and N respectively, which are given only in (4).