Practice | Hashtable

content Computer Science Arithmetic Aptitude Data Interpretation Logical Reasoning Verbal Reasoning Non-Verbal Reasoning

About About Privacy Policy

Hashtable

Home
Practice
PYQ
Mock Test
Register Free

Home Practice PYQ Mock Test Register Free

Home > Practice > Data Interpretation > Bar Graphs > Miscellaneous

71. Study the following pie-chart and bar graph and answer the questions that follows:
Percentage-wise distribution of Teachers in 6 Districts.

Number of males in each district out of 4500 Teachers.

In which district is the number of male teachers more than the number of female teachers?

A. B only

B. D only

C. Both B and E

D. Both E and F

Discuss

Solution:

\begin{aligned} Total number of teachers in: \\ A → \frac{14}{100} \times 4500 = 630 \\ B → \frac{16}{100} \times 4500 = 720 \\ C → \frac{28}{100} \times 4500 = 1260 \\ D → \frac{15}{100} \times 4500 = 675 \\ E → \frac{21}{100} \times 4500 = 945 \\ F → \frac{6}{100} \times 4500 = 270 \end{aligned}

	A	B	C	D	E	F
Males	200	400	600	100	500	100
Females	430	320	660	575	445	170

Clearly, the number of male teachers is more than the number of female teachers in B and E.

72. Study the following pie-chart and bar graph and answer the questions that follows:
Percentage-wise distribution of Teachers in 6 Districts.

Number of males in each district out of 4500 Teachers.

What is the ratio of the number of male teachers in District C to the number of female teachers in District B?

A. 11 : 15

B. 15 : 11

C. 15 : 8

D. 30 : 13

Discuss

Solution:

\begin{aligned} Total number of teachers in: \\ A → \frac{14}{100} \times 4500 = 630 \\ B → \frac{16}{100} \times 4500 = 720 \\ C → \frac{28}{100} \times 4500 = 1260 \\ D → \frac{15}{100} \times 4500 = 675 \\ E → \frac{21}{100} \times 4500 = 945 \\ F → \frac{6}{100} \times 4500 = 270 \end{aligned}

	A	B	C	D	E	F
Males	200	400	600	100	500	100
Females	430	320	660	575	445	170

(Number of male teachers in C) : (Number of female teachers in B)
= 600 : 320
= 15 : 8

73. Study the following pie-chart and bar graph and answer the questions that follows:
Percentage-wise distribution of Teachers in 6 Districts.

Number of males in each district out of 4500 Teachers.

The number of female teachers in District D is approximately what percent of the total number of teachers (both male & female) in District A?

A. 70%

B. 75%

C. 80%

D. 95%

Discuss

Solution:

\begin{aligned} Total number of teachers in: \\ A → \frac{14}{100} \times 4500 = 630 \\ B → \frac{16}{100} \times 4500 = 720 \\ C → \frac{28}{100} \times 4500 = 1260 \\ D → \frac{15}{100} \times 4500 = 675 \\ E → \frac{21}{100} \times 4500 = 945 \\ F → \frac{6}{100} \times 4500 = 270 \end{aligned}

	A	B	C	D	E	F
Males	200	400	600	100	500	100
Females	430	320	660	575	445	170

Female teacher in D = 575
Total number of teacher in A
= 200 + 430
= 630
∴ Required percentage

\begin{aligned} = (\frac{575}{630} \times 100) % \\ = \frac{5750}{63} % \\ = 91.2 % \\ \approx 90 % \end{aligned}

74. Study the following pie-chart and bar graph and answer the questions that follows:
Percentage-wise distribution of Teachers in 6 Districts.

Number of males in each district out of 4500 Teachers.

What is the difference between the number of female teachers in District F and the total number of teachers (both male and female) in District E?

A. 625

B. 775

C. 675

D. 725

Discuss

Solution:

\begin{aligned} Total number of teachers in: \\ A → \frac{14}{100} \times 4500 = 630 \\ B → \frac{16}{100} \times 4500 = 720 \\ C → \frac{28}{100} \times 4500 = 1260 \\ D → \frac{15}{100} \times 4500 = 675 \\ E → \frac{21}{100} \times 4500 = 945 \\ F → \frac{6}{100} \times 4500 = 270 \end{aligned}

	A	B	C	D	E	F
Males	200	400	600	100	500	100
Females	430	320	660	575	445	170

Number of female teachers in F = 170
Total number of teachers in E
= 500 + 445
= 945
∴ Required difference
= 945 - 170
= 775

75. The following is a horizontal bar diagram showing the accidents in which two-wheelers are involved with other objects. Study the diagram and answer the questions.
OBJECTS HIT

The difference in percentage between the accidents involving two-wheelers and other objects is respectively.

A. 77% more

B. 77% less

C. 54% more

D. 54% less

Discuss

Solution:

Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Percentage of accidents involving two wheelers =

\frac{230}{1000}

× 100 = 23%
Percentage of accidents involving two wheelers and other subjects =

\frac{770 \times 100}{1000}

= 77%
∴ Required difference = 77 - 23 = 54%

76. The following is a horizontal bar diagram showing the accidents in which two-wheelers are involved with other objects. Study the diagram and answer the questions.
OBJECTS HIT

The percentage of accidents in which pedestrians and cyclists are involved is -

A. 24%

B. 6%

C. 60%

D. 20.4%

Discuss

Solution:

Required Percentage

\begin{aligned} = (\frac{40 + 200}{1000}) \times 100 \\ = \frac{24000}{1000} \\ = 24 % \end{aligned}

77. The following is a horizontal bar diagram showing the accidents in which two-wheelers are involved with other objects. Study the diagram and answer the questions.
OBJECTS HIT

60% of the accidents are involved due to

A. Cars, buses, tanker lorry and pedestrians.

B. Cars, tanker lorry, bicycles and stationary vehicles.

C. Two-wheeler, cars, buses and stationary vehicles.

D. Two-wheelers, cars, buses and tanker lorry.

Discuss

Solution:

Two wheelers + Cars + Buses + Stationary vehicles
= 230 + 150 + 120 + 100
= 600
∴

\frac{600}{1000}

× 100 = 60%

78. The following is a horizontal bar diagram showing the accidents in which two-wheelers are involved with other objects. Study the diagram and answer the questions.
OBJECTS HIT

The percentage by which the accidents involving buses is less than the accidents involving tanker lorry is-

A. 6%

B. 4%

C. 40%

D. 28%

Discuss

Solution:

Required difference
=

\frac{160 - 120}{1000}

× 100
= 4%

79. The following is a horizontal bar diagram showing the accidents in which two-wheelers are involved with other objects. Study the diagram and answer the questions.
OBJECTS HIT

If the data of the bar diagram is represented by a pie-chart, and the angle of a sector of the pie-chart is 36°, then this sector represents the accidents involving.

A. Pedestrians

B. Bicycles

C. Buses

D. Stationary vehicles

Discuss

Solution:

\begin{aligned} ∴ 360^{\circ} = 1000 Accidents \\ 1^{\circ} = \frac{1000}{360^{\circ}} \\ 36^{\circ} = \frac{1000}{360^{\circ}} \times 36^{\circ} \\ = 100 Accidents \end{aligned}

It is the accidents of Stationary vehicles

80. The bar chart given below shows the percentage distribution of the production of various models of a mobile manufacturing company in 2007 and 2008. The total production in 2007 was 35 lakh mobile phones and in 2008 the production was 44 lakh. Study the chart and answer the following questions.
Percentage of six different types of mobiles manufactured by a company over two year.

If 85% of the D type mobile produced in each year were sold by the company, how many D type mobiles remained unsold?

A. 76,500

B. 93,500

C. 1,18,500

D. 1,22,500

Discuss

Solution:

'D' type production in 2007
= 35 ×

\frac{10}{100}

'D' type production in 2008
= 44 ×

\frac{10}{100}

Required Answer

\begin{aligned} = (35 \times \frac{10}{100} + 44 \times \frac{10}{100}) \times \frac{15}{100} \\ = 118500 \end{aligned}

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

Sign up for our newsletter

Are you passionate about opportunities in the realm of Computer Science within the government sector? Don't miss out on crucial updates, job openings, and career prospects tailored specifically straight to your inbox.

Email address

By subscribing, you agree with our Terms of Service and Privacy Policy.

Resources

Practice PYQ Mock Test

Company

About us Contact us Privacy policy Terms of service

Hashtable